Final answer:
To calculate the pAg+, determine the moles of AgNO₃ added, then calculate the concentration of Ag+ in the solution. Finally, take the negative logarithm of the Ag+ concentration to find the pAg+.
Step-by-step explanation:
The question is asking for the pAg+ following the addition of the given volumes of AgNO₃. To calculate the pAg+, we need to first determine the moles of AgNO₃ added to the solution. Then, we can use the moles of AgNO₃ to calculate the concentration of Ag+ in the solution. Finally, we can take the negative logarithm of the Ag+ concentration to find the pAg+.
To start, we need to determine the moles of AgNO₃ added. The moles of AgNO₃ can be calculated using the formula:
moles of AgNO₃ = volume of AgNO₃ (L) x molarity of AgNO₃ (mol/L)
moles of AgNO₃ = 0.05120 L x 0.05120 mol/L = 0.0026368 mol
Next, we can use the balanced equation AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq) to determine the moles of Ag+ in the solution. From the equation, we see that 1 mole of AgNO₃ produces 1 mole of Ag+. Therefore, the moles of Ag+ in the solution is also 0.0026368 mol.
Finally, we can calculate the Ag+ concentration using the formula:
Ag+ concentration = moles of Ag+ / volume of solution (L)
Ag+ concentration = 0.0026368 mol / 0.025 L = 0.1055 M
Now we have the Ag+ concentration, we can calculate the pAg+ using the formula:
pAg+ = -log10 (Ag+ concentration)
Applying the calculation:
pAg+ = -log10 (0.1055 M) = 0.98
Therefore, the pAg+ following the addition of the given volumes of AgNO₃ is approximately 0.98.