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A 25.0 ml sample of a sulfuric acid solution, H₂SO₄, was titrated to completion with 34.6 ml of 0.102 m potassium hydroxide, KOH. What was the concentration of the sulfuric acid solution?

User PatlaDJ
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Final answer:

To calculate the concentration of the sulfuric acid solution, the balanced chemical equation was used along with the molarity and volume of KOH. The concentration was determined to be 0.07064 M.

Step-by-step explanation:

To determine the concentration of the sulfuric acid solution, we need to use the titration data provided. First, we'll write down the balanced chemical equation for the titration of sulfuric acid with potassium hydroxide:

H2SO4 (aq) + 2KOH (aq) → K2SO4 (aq) + 2H2O (l)

From the equation, we can see that one mole of H2SO4 reacts with two moles of KOH. Using the molarity and volume of KOH, we can find the moles of KOH used in the titration:

Moles of KOH = 0.102 M × 0.0346 L = 0.0035322 mol KOH

Since it takes 2 moles of KOH to neutralize 1 mole of H2SO4, the moles of sulfuric acid will be half the moles of KOH:

Moles of H2SO4 = 0.0035322 mol KOH ÷ 2 = 0.0017661 mol H2SO4

Finally, we can calculate the molarity of the sulfuric acid solution using the moles of H2SO4 and the volume of the acid solution:

Molarity of H2SO4 = 0.0017661 mol H2SO4 ÷ 0.0250 L

Therefore, the concentration of the sulfuric acid solution is 0.07064 M.

User HowDoIDoComputer
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