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A 22.0 g particle is moving to the left at 21.0 m/s. How much work must be done on the particle to cause it to move to the right at 47.0 m/s ?

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Final answer:

The work done on the particle to cause it to move to the right at 47.0 m/s is 16.528 J.

Step-by-step explanation:

To calculate the work done on the particle, we need to use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. In this case, the particle has a mass of 22.0 g (or 0.022 kg) and initially moves to the left at a velocity of 21.0 m/s. The final velocity is given as 47.0 m/s to the right. We can use the equation:

Work = (1/2) * m * (vf^2 - vi^2)

Plugging in the values:

Work = (1/2) * 0.022 * (47^2 - 21^2) = 16.528 J

Therefore, the work that must be done on the particle to cause it to move to the right at 47.0 m/s is 16.528 J.

User Peter Perot
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