Question

Two hunters aim at a target. the probability that the first will hit it is 1/7 while the probability that the second will hit it is 3/5. find the probability that,

a) both will hit the target.
(b) only the first will hit it.
(c) one of them will hit it.
(d) both of them will miss it​.

Answer 1

The probability that both hunters will hit the target is 3/35. The probability that only the first hunter will hit the target is 2/35. The probability that one of them will hit the target is 50/35.

Step-by-step explanation:

a) The probability that both hunters will hit the target is found by multiplying the individual probabilities. So, the probability is (1/7) * (3/5) = 3/35.

b) The probability that only the first hunter will hit the target is calculated by subtracting the probability of the second hunter hitting the target from the probability of both hunters hitting the target. So, the probability is (1/7) - (3/35) = 2/35.

c) The probability that one of them will hit the target is calculated by adding the probabilities of the first hunter hitting the target and the second hunter hitting the target, and then subtracting the probability of both hunters hitting the target. So, the probability is (1/7) + (3/5) - (3/35) = 50/35.

d) The probability that both hunters will miss the target is found by subtracting the probability of both hunters hitting the target from 1. So, the probability is 1 - (3/35) = 32/35.