Question

Two negative charges, each of magnitude 12 x 10-⁶ C, are located at a distance of 12 cm from each other.

NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
What is the magnitude of the force exerted on each charge?

Answer 1

The magnitude of the force exerted on each charge is 900 N.

Step-by-step explanation:

The magnitude of the force exerted on each charge can be calculated using Coulomb's law. Coulomb's law states that the force between two charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.

In this case, the magnitude of each charge is 12 x 10-6 C and the distance between them is 12 cm (which is equal to 0.12 m).

Applying Coulomb's law, we have:

F = (k * q1 * q2) / r2

where F is the force, k is the electrostatic constant (9 x 109 N·m2/C2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

Plugging in the values, we get:

F = (9 x 109 * (12 x 10-6)2) / (0.12)2

Simplifying this equation gives:

F = 900 N

Therefore, the magnitude of the force exerted on each charge is 900 N.