Final answer:
To dilute 25 mL of a 10 M H₂SO₄ solution to a 0.13 M solution, you need to increase the volume to 1923.08 mL using the dilution equation M₁V₁ = M₂V₂.
Step-by-step explanation:
To determine the volume to which you should dilute 25 mL of a 10 M H₂SO₄ solution to obtain a 0.13 M H₂SO₄ solution, we use the dilution equation M₁V₁ = M₂V₂, where M₁ and V₁ are the molarity and volume of the concentrated solution, and M₂ and V₂ are the molarity and volume of the diluted solution, respectively.
Plugging the given values into the equation: (10 M) (25 mL) = (0.13 M) (V₂), we solve for V₂ to find the final volume necessary for the dilution.
V₂ = (10 M) (25 mL) / (0.13 M) = 250 mL / 0.13 = 1923.08 mL. Therefore, to obtain a 0.13 M solution from a 10 M solution, you should dilute the 25 mL of sulfuric acid to a total volume of 1923.08 mL.