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My distance west from Nashville t hours after noon is given by D=68t+35 miles.

a. D=68t+35
b. D=68t−35
c. D=35t+68
d. D=35t−68

1 Answer

3 votes

Final answer:

The student's question deals with displacement and vectors in mathematics, applying trigonometry to find horizontal and vertical components of motion in physics-related problems.

Step-by-step explanation:

The student's schoolwork question appears to involve displacement and vectors in a mathematics concept predominantly taught in physics. Specifically, it looks at finding the components of a displacement when moving in particular directions relative to a coordinate system, as well as related problems involving displacement and positions. Although the question about the distance west from Nashville is related to functions and might suggest algebra, the irrelevant parts of the question suggest a focus on vector components and displacement in two dimensions.

To solve such problems typically involves using trigonometric relationships to decompose a movement into its horizontal and vertical components (east/west and north/south). This requires an understanding of sine and cosine functions for determining the respective distances traveled in each direction (for example, x = rcos(θ) and y = rsin(θ), where x and y are the components, r is the magnitude of the displacement, and θ is the angle).

User David M Smith
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