Final answer:
To calculate the maximum possible speed of the toy car at position B, apply conservation of energy principles. Potential energy at position A is converted into kinetic energy at position B, yielding a maximum possible speed of approximately 4.2 m/s.
Step-by-step explanation:
To calculate the maximum possible speed of the toy car when it reaches position B, we can use the principle of conservation of energy. The potential energy (PE) at position A will be converted into kinetic energy (KE) at position B, assuming no energy is lost to friction or air resistance. The potential energy at position A is PE = mgh, where m is the mass of the toy car, g is the acceleration due to gravity, and h is the vertical height.
The kinetic energy at position B can be calculated using KE = \(\frac{1}{2}mv^{2}\), with v being the speed at position B. By setting the potential energy equal to the kinetic energy (PE = KE), we can solve for v, the speed at position B:
PE = mgh = \(\frac{1}{2}mv^{2}\) \(\rightarrow\) \(\frac{1}{2}mv^{2}\) = mgh \(\rightarrow\) v = \(\sqrt{2gh}\)
Plugging in the values provided (m = 0.04 kg, g = 9.8 N/(kg × g), and h = 90 cm = 0.9 m), we get:
v = \(\sqrt{2 \times 9.8 \times 0.9}\) \(\approx\) 4.2 m/s
Therefore, the maximum possible speed of the toy car when it reaches position B is approximately 4.2 m/s.