Final answer:
To determine the volume of 1.60 M Na3PO4 needed for 0.620 moles of Na ions, divide the moles of Na by 3 to find the moles of Na3PO4 and then divide again by the molarity. The calculated volume is 0.12919 L, which does not match any given options, suggesting there may be an error in the provided choices or the calculation.
Step-by-step explanation:
The question asks about the volume of Na3PO4 solution needed to obtain a certain amount of Na ions. To solve this problem, we first need to identify the number of moles of Na3PO4 that would contain 0.620 moles of Na ions. Since there are 3 moles of Na in one mole of Na3PO4, we need to divide the number of moles of Na ions by 3 to find the moles of Na3PO4:
Moles of Na3PO4 = 0.620 moles Na ÷ 3 = 0.2067 moles Na3PO4
Next, we use the molarity (M) of the Na3PO4 solution to find the volume required. The molarity of the solution is given as 1.60 M, which means there is 1.60 moles of solute per liter of solution. Therefore, the volume (V) needed is calculated as:
Volume (V) = Moles of Na3PO4 ÷ Molarity (M) = 0.2067 moles ÷ 1.60 mol/L = 0.12919 L
When the calculated volume does not match any options given in the question, it usually indicates a possible error in either the question's options or the calculation process. In this case, as none of the given answer options match, the next step would be to double-check the calculation, and if it's correct, discuss the discrepancy with the instructor.