114k views
4 votes
What is the resonance frequency of an lc circuit consisting of a 26.0 µf capacitor and a 0.010 h inductor?

User Corrinne
by
7.5k points

1 Answer

3 votes

Final answer:

The resonance frequency of an LC circuit can be calculated using the formula: Resonance frequency = 1 / (2π√(LC)). In this case, the inductance of the circuit is 0.010 H and the capacitance is 26.0 µF. By substituting these values into the formula, we can find the resonance frequency.

Step-by-step explanation:

The resonance frequency (also known as the natural frequency) of an LC circuit can be calculated using the formula:

Resonance frequency = 1 / (2π√(LC))

Where:

L is the inductance in henries (H)

C is the capacitance in farads (F)

π is a mathematical constant approximately equal to 3.14159

In this case, the inductance of the circuit is 0.010 H and the capacitance is 26.0 µF. To find the resonance frequency, we need to convert the units of capacitance to farads:

C = 26.0 µF = 26.0 × 10-6 F

Now we can substitute the values into the formula:

Resonance frequency = 1 / (2π√(0.010 × 26.0 × 10-6))

Calculating this expression will give us the resonance frequency of the LC circuit.

User Jinyoung Kim
by
7.0k points