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What mass of NaNo₃ is required to prepare 33.9 ml of solution of NaNo₃ with a molarity of 0.222m?

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Final answer:

To calculate the mass of NaNO₃ required to prepare a solution with a specified molarity and volume, multiply the molarity, volume, and molar mass of NaNO₃.

Step-by-step explanation:

To calculate the mass of NaNO₃ required to prepare a solution with a specified molarity and volume, we can use the formula:

mass = molarity x volume x molar mass

In this case, the molarity is 0.222m and the volume is 33.9 mL. The molar mass of NaNO₃ is 85 g/mol. Plugging these values into the formula, we get:

mass = 0.222m x 33.9 mL x 85 g/mol = 63.8722 g

Therefore, 63.8722 grams of NaNO₃ is required to prepare 33.9 mL of the solution.

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