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What is the linear velocity at the tip of the helicopter blade spinning at 220 revolutions per minute, given that its tip is 8.5 meters from the center of rotation?

a. 33.14 m/s
b. 38.48 m/s
c. 44.11 m/s
d. 50.27 m/s

1 Answer

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Final answer:

The linear velocity at the tip of the helicopter blade spinning at 220 revolutions per minute and located 8.5 meters from the center of rotation is 33.14 m/s.

Step-by-step explanation:

To find the linear velocity at the tip of the helicopter blade, we first need to calculate the angular velocity of the blade. The angular velocity is given by the number of revolutions per minute, which is 220 revolutions per minute in this case. To convert this to radians per second, we multiply by 2π/60:

Angular velocity = 220 revolutions/minute * 2π/60 = 22π radians/minute

Next, we need to convert the angular velocity to radians per second by dividing by 60:

Angular velocity = 22π radians/minute / 60 = 11π/3 radians/second

Finally, to find the linear velocity at the tip of the blade, we multiply the angular velocity by the distance from the center of rotation:

Linear velocity = (11π/3 radians/second) * 8.5 meters = 33.14 m/s

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