Final answer:
The diagonals of a regular pentagon are congruent because they are all sides of congruent isosceles triangles formed within the pentagon, derived from its equiangular and equilateral properties, and supported by the transitive property of equality.
Step-by-step explanation:
In proving that all diagonals of a regular pentagon have the same length, we look to the properties that define it: a polygon that is both equilateral and equiangular.
To prove the diagonals are congruent, consider any two adjacent vertices of the pentagon and label them as A and B. Since the pentagon is equilateral, we know AB is equal in length to the other sides. Now, consider the vertex opposite to side AB and label it as C. The diagonal AC is drawn from A to C. Since the pentagon is also equiangular, angles at each vertex are equal, forming isosceles triangles within the pentagon when diagonals are drawn.
By drawing all possible diagonals from vertex A, we form a series of triangles ACD, ACE, and so on. The Pythagorean theorem suggests that the sides of these triangles relate such that the square of one side plus the square of another side equals the square of the hypotenuse. Nonetheless, in a regular pentagon, the sides and angles are equal, so all isosceles triangles formed are congruent, and thus, all diagonals are equal in length.
This conclusion relies on the transitive property of equality (if AC = AE and AE = AD, then AC = AD), reaffirming that all diagonals (AC, AD, AE, etc.) are congruent. The constant properties of the regular pentagon allow us to determine that all the diagonals share the same length without individually measuring each one.