Question

A sample of xenon gas occupies a volume of 6.46 l at 441 K. If the pressure remains constant, at what temperature will this same xenon gas sample have a volume of 3.28 l?

A) 220.5 K
B) 368 K
C) 662 K
D) 882 K

Answer 1

To find the temperature at which the xenon gas sample will have a volume of 3.28 L, we can use the combined gas law. Plugging the given values into the equation, we find that the temperature is approximately 368 K.

Step-by-step explanation:

To solve this problem, we can use the combined gas law, which states that for a sample of gas when pressure and amount are kept constant:

11/1 = 22/2

Given that the initial volume (1) is 6.46 L and the initial temperature (1) is 441 K, and the final volume (2) is 3.28 L, we can solve for the final temperature (2):

11/1 = 22/2

(2.44 )(4.01 ) / 441 = (2.44 )(3.28 ) / 2

This equation can be rearranged to solve for 2:

2 = (2.44 )(3.28 ) / ((2.44 )(4.01 ) / 441 )

Calculating this gives:

2 ≈ 368

Therefore, at a temperature of approximately 368 K, the xenon gas sample will have a volume of 3.28 L.