Question

A photon has an energy of

2.16×10 ^−22J. What is its frequency? (Use

c=3.00×10 ^8 m/s, and Planck’s constant,
ℎ=6.626×10−34

J·s)

Answer 1

The frequency of the photon is approximately 3.26×10^11 Hz.

Step-by-step explanation:

To find the frequency of a photon with an energy of 2.16×10-22 J, we can use the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency.

So, rearranging the equation, we have f = E/h.

Substituting the given values, we get: f = (2.16×10-22 J) / (6.626×10-34 J·s).

Simplifying the calculation, we find that the frequency of the photon is approximately 3.26×1011 Hz.