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What maximum tension, in meganewtons, could a glass optical fiber with a diameter of 11.1 μm support, given its tensile strength of 53.0✕10^6 N/m^2?

a) 41.5 MN
b) 46.5 MN
c) 50.5 MN
d) 55.5 MN

User Jon Hanson
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1 Answer

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Final answer:

The maximum tension a glass optical fiber can support is approximately 46.4 MN.

Step-by-step explanation:

To calculate the maximum tension that a glass optical fiber can support, we can use the formula for stress, which is force divided by area. The tensile strength of the fiber is given as 53.0 x 106 N/m2. We need to convert the diameter of the fiber to meters by dividing it by 106. Then, we can calculate the maximum tension using the formula:

Tension = Stress x Area

Area = πr2, where r is the radius of the fiber.

By substituting the values and simplifying, we find:

Tension = (53.0 x 106 N/m2) x (π(5.55 x 10-6)2)

Tension = 46.4 MN (approximately)

User Mohan Gulati
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