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A newly discovered metalloprotein, which contains two atoms of Zn per molecule of protein, is found to be 0.622% Zn by mass. Calculate the molar mass of the metalloprotein. (Provide the answer in one sentence.)

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Final answer:

The molar mass of the metalloprotein, which is 0.622% Zn and contains two atoms of Zn per molecule, is calculated to be approximately 21000 g/mol using the molar mass of Zn.

Step-by-step explanation:

To calculate the molar mass of the metalloprotein that is 0.622% Zn by mass, with each molecule containing two atoms of Zn, we can use the molar mass of Zn which is 65.39 g/mol. Knowing that 0.622% of the metalloprotein's mass is Zn, we can set up a proportion:

(2 × 65.39 g/mol) / Molar Mass of protein = 0.622 / 100

Rearranging to solve for the molar mass of the protein, we get:

Molar Mass of protein = (2 × 65.39 g/mol) / (0.622 / 100)

Doing this calculation, the molar mass of the metalloprotein is approximately 21000 g/mol.

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