Final answer:
The molar mass of the metalloprotein, which is 0.622% Zn and contains two atoms of Zn per molecule, is calculated to be approximately 21000 g/mol using the molar mass of Zn.
Step-by-step explanation:
To calculate the molar mass of the metalloprotein that is 0.622% Zn by mass, with each molecule containing two atoms of Zn, we can use the molar mass of Zn which is 65.39 g/mol. Knowing that 0.622% of the metalloprotein's mass is Zn, we can set up a proportion:
(2 × 65.39 g/mol) / Molar Mass of protein = 0.622 / 100
Rearranging to solve for the molar mass of the protein, we get:
Molar Mass of protein = (2 × 65.39 g/mol) / (0.622 / 100)
Doing this calculation, the molar mass of the metalloprotein is approximately 21000 g/mol.