Final answer:
Using the thrust force and velocity, the delivered power of a jet aircraft with given parameters is calculated to be approximately 5475927.2 W, which does not match the provided options.
Step-by-step explanation:
To find the delivered power by a jet aircraft traveling at 202 m/s in horizontal flight, where the engine takes in air at a rate of 35.2 kg/s and burns fuel at a rate of 2.35 kg/s, with exhaust gases ejected at 924 m/s, we can use the formula for power in terms of thrust force and velocity (P = Fv).
First, the change in momentum per second of the exhaust gases is the mass flow rate times the exhaust velocity relative to the aircraft. The change in momentum per second is also the thrust force (F).
F = (mass flow rate of air + mass flow rate of fuel) × (ejection velocity - aircraft velocity)
F = (35.2 kg/s + 2.35 kg/s) × (924 m/s - 202 m/s)
F = 37.55 kg/s × 722 m/s
F = 27108.6 N
Then, the delivered power is the thrust force times the velocity of the aircraft.
P = F × aircraft velocity
P = 27108.6 N × 202 m/s
P = 5475927.2 W
P = 5.4759272 × 10^6 W, which is approximately 5.48 MW (Option B, 8,192,000 W, does not seem correct with our calculation, but the given options do not match our calculated value. Be sure to check all calculations and ensure that proper units and formulas are being used).