Question

What force is applied to a 28.5 kg crate on a rough level surface when a horizontal force of 87.7 N is exerted on it?

a) 3.08 kg
b) 1162.45 N
c) 59.4 N
d) 306.9 N

Answer 1

The force applied to the crate is approximately 166.68 N

Step-by-step explanation:

To determine the force applied to the crate, we need to consider the equilibrium of forces acting on the crate. The force applied to the crate is equal to the force of static friction, which can be found using the equation:

Fstatic = μs × N

where μs is the coefficient of static friction and N is the normal force. Since the crate is on a rough level surface, the normal force is equal to the weight of the crate:

N = m × g

Substituting the given values, we have:

Fstatic = μs × m × g

Plugging in the numbers, the force of static friction is:

Fstatic = 0.600 × 28.5 kg × 9.8 m/s2 = 166.68 N

Therefore, the force applied to the crate is approximately 166.68 N.