Final answer:
The height of the center of gravity for a car on a 40° slope with a width of 2.2 meters is approximately 0.959 meters, which does not match any of the provided options.
Step-by-step explanation:
To determine the height of the center of gravity of a car that can drive across a hill with a 40° slope, given the vehicle's width is 2.2 meters, we use the concept of static stability. The maximum height of the center of gravity can be found by using the formula:
h = w / 2 * tan(θ)
where h is the height of the center of gravity, w is the width of the vehicle (2.2 meters) and θ is the slope angle (40°). Plugging in the values:
h = 2.2 / 2 * tan(40°) ≈ 0.959 meters
None of the provided options A) 1.544 meters, B) 1.745 meters, C) 1.908 meters, or D) 2.076 meters match the calculated value. Therefore, if these were the options provided in a multiple-choice question, there would be an issue with the question itself or the calculation should be revisited. However, assuming the calculation is correct, the height of the center of gravity would be approximately 0.959 meters.