Question

A baseball is thrown with an initial velocity of 13 m/s at an angle about the horizontal. What are the magnitude and direction of the ball's velocity 1 second after it is thrown?

A) Magnitude: 13 m/s, Direction: The same as the initial angle
B) Magnitude: 13 m/s, Direction: Opposite to the initial angle
C) Magnitude: 13 m/s, Direction: Horizontal
D) Magnitude: 13 m/s, Direction: Vertical

Answer 1

The magnitude of the ball's velocity 1 second after it is thrown is approximately 13.4 m/s. The direction of the ball's velocity 1 second after it is thrown is the same as the initial angle.

Step-by-step explanation:

The magnitude of the ball's velocity 1 second after it is thrown can be determined by finding the horizontal and vertical components of the initial velocity. The horizontal component remains constant, so it will still be 13 m/s. The vertical component, however, will change due to the force of gravity. In 1 second, the vertical component will decrease by 9.8 m/s (the acceleration due to gravity) to become 3.2 m/s. Therefore, the magnitude of the ball's velocity 1 second after it is thrown is approximately 13.4 m/s.

As for the direction of the ball's velocity, it will still be in the same direction as the initial angle. This is because only the vertical component changes due to gravity, while the horizontal component remains constant. So the direction of the ball's velocity 1 second after it is thrown is the same as the initial angle.