Final answer:
To find the proportion of bottles with volumes greater than 1008 mL in a normal distribution with a mean volume of 1008 mL and a standard deviation of $ mL, we calculate the z-score and use a standard normal distribution table or calculator to find the proportion. The correct answer is 0.1587.
Step-by-step explanation:
To find the proportion of bottles with volumes greater than 1008 mL in a normal distribution with a mean volume of 1008 mL and a standard deviation of $ mL, we need to find the area under the curve to the right of 1008 mL. This can be done by finding the z-score, which is calculated as (1008 - mean) / standard deviation. Once we have the z-score, we can use a standard normal distribution table or a calculator to find the proportion. The correct answer is option D) 0.1587.