Question

Find a point on the perpendicular line from part a that is not the y-intercept. enter the correct answers in the boxes. with a known value of x , find the corresponding value of y . For x=8 , y=___? . Therefore, a point other than the y-intercept through which the perpendicular line passes is?

a) y=4x−2
b) y=−2x+8
c) y=−2x−6
d) y=4x+10

Answer 1

To find a point on the perpendicular line, calculate the slope of the original line and then use a known value of x to find the value of y on the perpendicular line.

Step-by-step explanation:

To find a point on the perpendicular line from the given equation that is not the y-intercept, we need to first find the slope of the given line which is the negative reciprocal of the slope of the original line. The given equation is y = 4x−2, so the slope is 4. The negative reciprocal of 4 is -1/4. So, the slope of the perpendicular line is -1/4.

Next, we need to find a point on the perpendicular line. Let's choose x = 8.

Substitute x = 8 into the equation y = -1/4x + b and solve for y. y = -1/4(8) + b = -2 + b.

So, when x = 8, y = -2 + b. The point on the perpendicular line for x = 8 is (8, -2 + b).