Final answer:
To find the osmotic pressure of a pepsin solution, calculate the molarity, convert the temperature to Kelvin, and then use the osmotic pressure equation π = iMRT. After calculating the pressure in atm, convert it to mmHg to get the final osmotic pressure in mmHg.
Step-by-step explanation:
To calculate the osmotic pressure of a 0.150-g sample of pepsin in 40.0 ml of an aqueous solution at 30 °C, we need to use the osmotic pressure equation π = iMRT, where π is osmotic pressure, i is the van't Hoff factor (which is 1 for non-electrolytes like pepsin), M is the molarity of the solution, R is the gas constant (0.0821 L·atm/(K·mol)), and T is the temperature in Kelvin.
First, we convert 30 °C to Kelvin (T = 30 + 273.15 = 303.15 K) and then calculate the number of moles of pepsin (n = mass/molar mass = 0.150 g / 35000 g/mol = 4.29 x 10-6 mol).
Next, we find the molarity (M = moles/volume in liters = 4.29 x 10-6 mol / 0.040 L = 1.0725 x 10-4 M). Using the osmotic pressure equation: π = (1)(1.0725 x 10-4 M)(0.0821 L·atm/(K·mol))(303.15 K).
After performing this calculation, we must convert atm to mmHg (1 atm = 760 mmHg), which gives us the final osmotic pressure in mmHg.
To get the final value, calculate this equation to find the osmotic pressure in atm and then multiply by 760 to convert to mmHg. The correct choice from the provided options would be the result closest to this calculation.