Final answer:
By using the formula E = hf and substituting the given values, the frequency of the photon with an energy of 6.6 x 10^-19 J is calculated to be 1 x 10^15 Hz.
Step-by-step explanation:
To find the frequency of a photon given its energy, we can use the formula E = hf, where E is energy, h is Planck's constant, and f is frequency. Given that the energy (E) of the photon is 6.6 x 10^-19 J and Planck's constant (h) is 6.63 x 10^-34 J·s, we can solve for the frequency (f) by rearranging the formula to f = E/h.
Substituting the given values into the equation, we get f = (6.6 x 10^-19 J) / (6.63 x 10^-34 J·s) = 9.95 x 10^14 s^-1, which we can round to 1 x 10^15 Hz.
Therefore, the correct answer is d) 1 x 10^15 Hz.