Final answer:
In a second order reaction, doubling the initial concentration will quadruple the rate of reaction.
Step-by-step explanation:
In a second order reaction, if the initial concentration doubles, the rate will quadruple.
For example, let's say the rate of the reaction is given by the equation rate = k[A]², where [A] represents the concentration of the reactant.
If the initial concentration of A is doubled, the new concentration becomes 2[A]. Plugging this into the rate equation, we get rate = k(2[A])² = 4k[A]².
Therefore, doubling the initial concentration in a second order reaction will result in the rate of the reaction increasing fourfold.