Question

If a solution of methanol in water is prepared by mixing together 128 g of methanol, what is the final volume of the solution if the density of methanol is 0.79 g/cm3?

Answer 1

By dividing the mass of methanol (128 g) by its density (0.79 g/mL), we determine the final volume of the methanol solution to be approximately 162.03 mL. This calculation assumes that the volume does not change upon mixing with water.

Step-by-step explanation:

To calculate the final volume of a methanol solution when 128 g of methanol is mixed with water, one must use the density of methanol. The density of methanol is given as 0.79 g/cm³ (which is equivalent to 0.79 g/mL since 1 cm³ is equal to 1 mL).

To find the volume that these 128 g of methanol will occupy, we can use the formula for density, which is:

Density = Mass / Volume

Rearranging this for volume gives:

Volume = Mass / Density

Inserting the numbers:

Volume = 128 g / 0.79 g/mL

So, the Volume = 162.03 mL. Thus, the final volume of the methanol solution will be approximately 162.03 mL, assuming negligible volume change upon mixing with water.