Question

What is the output from the following code segment when the input is (1, 4, 2, 5, -2, 3)

cnt = 0
t = 0
while (cnt < 6):
-> num = int ( input () )
-> if ( ( num > 0 and ( num % 2 == 1) ):
--> t = t + num
-> cnt = cnt + 1
print ( t, end="")

Answer 1

The code summates all positive odd numbers from the input sequence (1, 4, 2, 5, -2, 3), resulting in an output of 9.

Step-by-step explanation:

The code segment in question is designed to receive six inputs and calculate the sum of positive odd numbers from those inputs. Given the input sequence (1, 4, 2, 5, -2, 3), the code will execute in the following manner:

• It initializes cnt to 0 and t to 0.
• Then, it starts a while loop that runs until cnt is less than 6.
• The code reads an integer input and checks if it is positive and odd.
• If it is, it adds the number to t.
• Regardless of the number being positive and odd or not, it increments cnt by 1.

Going through the inputs one by one, the code adds up 1, 5, and 3 (all positive odd numbers) to get t = 9.

Therefore, the output of the code when the input is (1, 4, 2, 5, -2, 3) is 9.