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What is the equation of the line that goes through \((-3, -1)\) and \((3, 3)\)?

- a. \(3x + 2y = 15\)
- b. \(3y - 2x = 15\)
- c. \(3x - 2y = 3\)
- d. \(2x - 3y = -3\)

1 Answer

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Final answer:

The equation of the line that goes through (-3, -1) and (3, 3) is y = (2/3)x + 1, which is equivalent to option c. 3x - 2y = 3.

Step-by-step explanation:

The equation of the line that goes through (-3, -1) and (3, 3) can be found using the slope-intercept form of a linear equation, y = mx + b, where m is the slope of the line and b is the y-intercept.

Step 1: Calculate the slope (m) using the formula (y2 - y1) / (x2 - x1).
m = (3 - (-1)) / (3 - (-3)) = 4 / 6 = 2/3.

Step 2: Substitute the slope (m) and the coordinates of one of the points into the equation y = mx + b to solve for b.
-1 = (2/3)(-3) + b
-1 = -2 + b
b = -1 + 2 = 1.

Therefore, the equation of the line is y = (2/3)x + 1, which is equivalent to option c. 3x - 2y = 3.

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