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Use a graphing calculator to perform a linear regression and find the correlation coefficient for the set of data. Round to the nearest hundredth.

X 1, 2, 3, 4, 5
y 1.5 2.6 1.5 3.3 1.8

STATISTICS
r(powered by 2)=0.5703
r=0.7552

PARAMETERS
m = 0.377381
b = 1.08929

Correlation coefficient:

RESIDUALS
e1

User Konsumer
by
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1 Answer

2 votes

The linear regression of the set of data is y = 0.13x + 1.75 and the correlation coefficient is 0.2604

Finding the linear regression of the set of data

From the question, we have the following parameters that can be used in our computation:

X 1, 2, 3, 4, 5

y 1.5 2.6 1.5 3.3 1.8

Using a graphing tool, we have the following summary

  • Sum of X = 15
  • Sum of Y = 10.7
  • Mean X = 3
  • Mean Y = 2.14
  • Sum of squares (SSX) = 10
  • Sum of products (SP) = 1.3

The regression equation is represented as

y = bx + a

Where

b = SP/SSx = 1.3/10 = 0.13

a = My - bMx = 2.14 - (0.13*3) = 1.75

So, we have

y = 0.13x + 1.75

For the correlation coefficient, we have the following summary

x values

∑ = 15

Mean = 3

∑(X - Mx)² = SSx = 10

y values

∑ = 10.7

Mean = 2.14

∑(Y - My)² = SSy = 2.492

x and y Combined

n = 5

∑(X - Mx)(Y - My) = 1.3

r Calculation

r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

So, we have

r = 1.3 / √((10)(2.492))

Evaluate

r = 0.2604

Hence, the correlation coefficient is 0.2604

User Rachwa
by
7.2k points