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The hotel purchases a large photo for its newly renovated lobby, the perimeter of the photo is 300 inches, the width is 6 inches more three times the height. Find the dimensions of the photo

User TroySteven
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Final answer:

To find the dimensions of the photo, we assume the height is H and therefore the width is 3H + 6. Setting up the perimeter equation and solving for H yields a height of 36 inches. The width calculates to be 114 inches.

Step-by-step explanation:

The student is seeking to find the dimensions of a large photo with a perimeter of 300 inches and the width being 6 inches more than three times the height. To solve for the dimensions, we start by denoting the height as H inches and thus the width will be 3H + 6 inches. The perimeter of a rectangle is calculated as 2(height + width), which gives us the equation:

2(H + 3H + 6) = 300

Simplifying we have:

8H + 12 = 300

8H = 288

H = 36

When we plug the height back into the width equation, we get:

Width = 3(36) + 6 = 108 + 6 = 114 inches

Therefore, the dimensions of the photo are 36 inches in height and 114 inches in width.

User JWWalker
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