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If [K]in is changed to 5mM, what happens to EK?

User Indyfromoz
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Final answer:

The value of EK will depend on the specific reaction being considered.

Changing the intracellular potassium concentration to 5 mM will affect the equilibrium potential (EK) for potassium, which can be calculated using the Nernst equation.

Step-by-step explanation:

When the concentration of [K]in is changed to 5mM, the value of EK, which represents the equilibrium constant, will depend on the specific reaction being considered. The equilibrium constant, denoted as K, is a measure of the extent to which reactants are converted into products at equilibrium. Therefore, changing the concentration of [K]in may result in a different value for EK.

Changing the intracellular potassium concentration to 5 mM will affect the equilibrium potential (EK) for potassium, which can be calculated using the Nernst equation.

When the concentration of the intracellular potassium ([K]in) is changed to 5 mM, the Nernst equation is used to determine the effect on the equilibrium potential for potassium (EK). The Nernst equation, EK = (RT/zF) * ln([K]out/[K]in), where R is the gas constant, T is the temperature in Kelvin, z is the valence of the ion, F is Faraday's constant, and [K]out and [K]in are the extracellular and intracellular potassium concentrations, respectively. As [K]in increases, the natural logarithm term decreases, leading to a decrease in the magnitude of EK.

User Jamie Hamick
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