Question

The scientist then performs an experiment adding a plasmid to the bacterial cell to determine which mutation is in the DNA‑binding protein and which is in the DNA‑binding site. The experimental setup is listed in the table, wherein a minus indicates a loss‑of‑function mutation, and a plus indicates the wild‑type allele.

Experiment |Bacterial cell | Plasmid

How will nop1 and nop2 be expressed if huh1 encodes the DNA‑binding protein and huh2 is a mutation in the binding site?

How will nop1 and nop2 be expressed if huh2 encodes the DNA‑binding protein and huh1 is a mutation in the binding site?

Answer 1

If huh1 encodes the DNA-binding protein and huh2 is a mutation in the binding site, the expression of nop1 and nop2 will depend on the function of huh1. If huh2 encodes the DNA-binding protein and huh1 is a mutation in the binding site, the expression of nop1 and nop2 will depend on the function of huh2.

Step-by-step explanation:

In the first scenario, where huh1 encodes the DNA-binding protein and huh2 is a mutation in the binding site, the expression of nop1 and nop2 will be dependent on the function of huh1. If huh1 is mutated and unable to bind to the DNA-binding site, then nop1 and nop2 will not be expressed. On the other hand, if huh1 is functioning properly, then nop1 and nop2 will be expressed as usual.

In the second scenario, where huh2 encodes the DNA-binding protein and huh1 is a mutation in the binding site, the expression of nop1 and nop2 will be dependent on the function of huh2. If huh2 is mutated and unable to bind to the DNA-binding site, then nop1 and nop2 will not be expressed. However, if huh2 is functioning properly, then nop1 and nop2 will be expressed as usual.