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Suppose that you have the following declaration.

enum cars {FORD, GM, TOYOTA, HONDA};
cars domesticCars = FORD;

The statement:
domesticCars = static_cast(domesticCars + 1);

sets the value of domesticCars to _____.
a. FORD
b. GM
c. TOYOTA
d. HONDA

User Mobile Ben
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1 Answer

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Final answer:

The statement sets the value of domesticCars to GM. The static_cast is used to convert the integer result back to the cars enumeration type after incrementing the value by 1.

Step-by-step explanation:

The given code is in the context of an enumeration representing various car brands. In this snippet of code, enum cars {FORD, GM, TOYOTA, HONDA}; creates an enumeration with the car brands and then a variable domesticCars of the enum type cars is assigned the value FORD.

The following statement:
domesticCars = static_cast<cars>(domesticCars + 1);
uses static_cast to convert the integer result of (domesticCars + 1) back to the enum type cars. Since domesticCars was initially set to FORD (which under most compilers corresponds to 0), adding 1 to it would lead to the next item in the enum list, which is GM. Therefore, this statement sets the value of domesticCars to GM.

The statement domesticCars = static_cast<cars>(domesticCars + 1); sets the value of domesticCars to b. GM.

Let's break down the statement. The static_cast function is used to convert the value of domesticCars + 1 to the type cars. Since domesticCars has the value FORD, adding 1 to it gives us GM. The static_cast then assigns this new value to domesticCars.

So, after the statement is executed, domesticCars will have the value GM.

User RecuencoJones
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