Final answer:
The given C++ code results in altering the values of int1 and int2 through pointer operations, and the output is '57 80'.
Step-by-step explanation:
The output of the provided C++ code involves manipulating variables using pointers. Initially, int1 is set to 26 and int2 is set to 45. The pointer int1ptr is set to the address of int1, and int2ptr is set to the address of int2. Following the pointer dereferencing and assignments, int1 is changed to 89, and int2 is changed to 62. Afterwards, int1ptr is pointed to the same address as int2ptr and is then dereferenced to set the value of int2 (where both pointers now point) to 80. Finally, int1 is directly set to 57. Therefore, when we output int1 and int2, the result is '57 80'.
The output of the given C++ code is 57 80.
Let's break down the code step by step:
Two integer variables, int1 and int2, are initialized with the values 26 and 45, respectively.
Two integer pointers, int1ptr and int2ptr, are declared and assigned the addresses of int1 and int2, respectively.
The value pointed to by int1ptr (which is int1) is changed to 89, and the value pointed to by int2ptr (which is int2) is changed to 62.
The value of int1ptr is updated to the value of int2ptr. Now, both pointers point to int2.
The value pointed to by int1ptr (which is int2) is changed to 80.
The value of int1 is changed to 57.
The final output of int1 and int2 is displayed as 57 80.