Question

What should be the output from this code segment?

for( int i = 0; i < 10; i++)
{
. . .
}
cout << i << endl;
a) 10
b) 9
c) 0
d) The variable i is undefined in this scope, so this should not compile

Answer 1

The output of the code will be a compiler error indicating that the variable 'i' is undefined in the scope where the 'cout' statement is trying to access it, as 'i' is only defined within the for-loop.

Step-by-step explanation:

You have asked what the output of the given code segment would be, particularly the value of i after the loop has finished executing. The answer is d) The variable i is undefined in this scope, so this should not compile. The reason is that the variable i is declared within the for-loop and its scope is limited to the loop itself. Once the loop terminates, the variable i no longer exists in the scope where the cout statement is trying to access it. Therefore, the compiler will give an error, indicating that i is undefined.