Question

What is the static lung compliance (Cs) when the returned tidal volume is 500 mL, baseline pressure is zero, and the Pplat reading is 25 cm H2O?

a.0.02 L/cm H2O
b.2.0 L/cm H2O
c.0.2 L/cm H2O
d.2.0 L/cm H2O

Answer 1

The static lung compliance (Cs) when the returned tidal volume is 500 mL and the Pplat reading is 25 cm H2O is 0.02 L/cm H2O.

Step-by-step explanation:

The static lung compliance (Cs) is calculated by dividing the change in lung volume (in liters) by the change in transpulmonary pressure (in cm H2O). In this case, the tidal volume is 500 mL, which is equivalent to 0.5 L, and the plateau pressure (Pplat) is 25 cm H2O.

The formula for static lung compliance is:

Cs = ΔV / ΔP

Where:

• ΔV is the change in lung volume, and
• ΔP is the change in transpulmonary pressure.

Using the given values:

Cs = 0.5 L / 25 cm H2O

Cs = 0.02 L/cm H2O

The correct answer is: a.0.02 L/cm H2O.