Answer:
Explanation:
Equation of circle is, (x-h)^2+ (y-k)^2=r .......(eqn1)
where, (h,k) is the center and r is the radius.
therefore, from the question by rearranging the equation,
x² + y² + 4x − 6y + 12=0
viz, (x² +4x+4) + (y²-6y+9)-1=0
(x+2)^2 + (y-3)^2=1
therefore from eqn1, (-2,3) is the center and radius is 1