Final answer:
The equilibrium constant expression (Kc) for the reaction is Kc = [Cr₃⁺][Ag]³ / [Cr][Ag⁺]³.
Step-by-step explanation:
The equilibrium constant expression (Kc) for the given reaction:
Cr(s) + 3 Ag⁺(aq) ↔ Cr₃⁺(aq) + 3 Ag(s)
is:
Kc = [Cr₃⁺][Ag]³ / [Cr][Ag⁺]³
The equilibrium constant expression is derived by taking the concentrations of the products raised to their stoichiometric coefficients divided by the concentrations of the reactants raised to their stoichiometric coefficients.
In this case, the stoichiometric coefficients are 1 for Cr and Cr₃⁺, and 3 for Ag⁺ and Ag.
Therefore, the equilibrium constant expression is Kc = [Cr₃⁺][Ag]³ / [Cr][Ag⁺]³.