Final answer:
The acid in the reaction is HSO₄⁻ and the base is NH₃. The equilibrium of the reaction will lie predominantly to the right because the conjugate acid-base pair formed by NH₃/NH₄⁺ is weaker than the pair formed by HSO₄⁻/SO₄²⁻.
Step-by-step explanation:
The acid in the reaction is HSO₄⁻ and the base is NH₃. The conjugate acid of HSO₄⁻ is SO₄²⁻ and the conjugate base of NH₃ is NH₄⁺.
The equilibrium of the reaction will lie predominantly to the right because the conjugate acid-base pair formed by NH₃/NH₄⁺ is weaker than the pair formed by HSO₄⁻/SO₄²⁻.
An acid-base equilibrium always favors the side with the weaker acid and base, which in this case is on the right side of the reaction.