Question

Me:

Chemistry
EDTA is a triprotic acid, which means that it releases 3 three protons when reacted with a base.
Suppose it takes 74.80 mL of a sodium hydroxide (NaOH) solution to react with 0.4573 grams of
EDTA (molar mass: 292.244 g/mol). Then 10.00 mL of HCI solution is pipetted into an Erlenmeyer
flask. This HCI solution requires 37.50 mL of the NaOH solution for neutralization. Determine the
molarity of the HCI solution.

Answer 1

To find the molarity of the HCl solution, you can use the mole ratio between HCl and NaOH and the volume of NaOH solution needed for neutralization. By calculating the moles of NaOH and HCl, you can determine the molarity of HCl. molarity HCl = 0.00748 mol / 0.010 L = 0.748 M

Step-by-step explanation:

To determine the molarity of the HCl solution, we can use the mole ratio between HCl and NaOH, as well as the volume of NaOH solution required for neutralization. From the given information, we know that 0.4573 grams of EDTA reacts with 74.80 mL of NaOH solution. This can be used to determine the concentration of NaOH in the solution, which is then used to find the molarity of the HCl solution.

First, calculate the moles of NaOH using its molar mass:

moles NaOH = (74.80 mL)(0.10 mol/L) = 0.00748 mol

Since the mole ratio between HCl and NaOH is 1:1, the moles of HCl is also 0.00748 mol. Now we can calculate the molarity of HCl:

molarity HCl = moles HCl / volume HCl

molarity HCl = 0.00748 mol / 0.010 L = 0.748 M