Question

What is the molarity of Cl1- in a 735 mL solution that contains 0.049 moles of SnCl₄?

a) 0.067 M
b) 0.0335 M
c) 0.066 M
d) 0.033 M

Answer 1

The molarity of Cl1- in the solution is 0.067 M.

Step-by-step explanation:

To find the molarity of Cl1- in the solution, we need to consider the stoichiometry of the compound SnCl₄. Since there is one chloride ion (Cl1-) for every SnCl₄ molecule, the moles of Cl1- will be equal to the moles of SnCl₄. Given that the solution contains 0.049 moles of SnCl₄ and has a volume of 735 mL, we can calculate the molarity of Cl1- as follows:

Molarity = Moles of solute / Volume of solution in liters

Molarity of Cl1- = 0.049 moles / 0.735 liters = 0.067 M

Therefore, the molarity of Cl1- in the solution is 0.067 M, which corresponds to option a) 0.067 M.