Answer:
The radius is
![√(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/q4m12k31i9z5su1n5q1g8upmbczk5yq26q.png)
The diameter is
![2 √(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ivs0mk6wu5p6ojhuj0q5jqxjm1pfro9yu3.png)
Explanation:
The area of the circle is represent as
![a = \pi * r {}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/j8vx0u1oqypbajo70khbvk3hkumdosf22n.png)
Where r is the radius and a is the area. Since pi is a irrational number, we won't focus on doing nothing with that instead we just take the sqr root of both sides to find the r or radius.
![√(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/q4m12k31i9z5su1n5q1g8upmbczk5yq26q.png)
Which is the radius and it cant be simplified so the radius is
![√(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/q4m12k31i9z5su1n5q1g8upmbczk5yq26q.png)
The diameter is twice longer than the radius so we
![2 * √(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ozs5hkqhkjywcmoc2ywij73ueej8l0emyy.png)
Which is
![2 √(29)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ivs0mk6wu5p6ojhuj0q5jqxjm1pfro9yu3.png)