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What is the solution set of the equation ∣4j∣+2=2−1∣

∣1j∣, where j
≠0,−2? a) {2}{2} b) {−1,1}{−1,1} c) {1}{1} d) {−1,2}{−1,2}

1 Answer

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Final answer:

The solution set of the equation |4j| + 2 = 2 - 1||1j|| is { -0.4 }.

Step-by-step explanation:

To find the solution set of the equation |4j| + 2 = 2 - 1||1j||, we can start by simplifying both sides. First, we can combine like terms on the right side of the equation, giving us:

|4j| + 2 = -1|1j|

Next, we can rewrite the absolute value expressions as follows:

4j + 2 = -1(1j)

Simplifying further, we have:

4j + 2 = -j

Now, we can solve for j by isolating the variable on one side of the equation. Subtracting 4j from both sides, we get:

5j + 2 = 0

Subtracting 2 from both sides, we have:

5j = -2

Finally, dividing both sides by 5 gives us the solution:

j = -0.4

So, the solution set of the equation is { -0.4 }.

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