Final answer:
The problem presented is about two runners where one runs at 2 mph faster than the other, and they supposedly meet after 1 hour and 6 minutes. However, the standard equation using distance, speed, and time does not provide a logical solution as the runners, if always moving in the same direction, would not meet under the conditions given. Further information or clarification is needed to solve this problem.
Step-by-step explanation:
To solve the problem, let's identify the variables and create an equation. Let's assume the slower runner runs at a speed of x mph. Therefore, the faster runner runs at x + 2 mph. Since they meet after 1 hour and 6 minutes, which is 1 + 6/60 hours or 1.1 hours, we can set up the equation based on the fact that distance equals speed multiplied by time (d = rt).
For the slower runner: d = x × 1.1
For the faster runner: d = (x + 2) × 1.1
Since they meet at the same point, the distances they cover must be the same. Thus, we have:
x × 1.1 = (x + 2) × 1.1
It seems there has been a misunderstanding in the question. The question, as posed, cannot lead to a logical solution because they would never meet if they were running in the same direction and one runner is always faster than the other. The question might be missing additional information (like they run in opposite directions or start from different points and run towards each other), or it could have been phrased incorrectly.