Final answer:
The charge stored in the 250 µF capacitor when 110 V is applied is 27,500 µC.
Step-by-step explanation:
To find the charge stored in a capacitor when a voltage is applied, you can use the formula:
Q = CV
Where Q is the charge, C is the capacitance of the capacitor, and V is the voltage applied.
In this case, the capacitance is given as 250 µF and the voltage is 110 V. Plugging these values into the formula:
Q = (250 µF)(110 V) = 27,500 µC
Therefore, when 110 V is applied to the capacitor, a charge of 27,500 µC is stored in it.