Final answer:
5.25 moles of water are produced from 10.5 grams of hydrogen gas using the stoichiometry of the balanced chemical equation for water formation.
Step-by-step explanation:
To calculate how many moles of water are produced from 10.5 grams of hydrogen gas, we need to use the balanced chemical equation for the reaction between hydrogen and oxygen to form water:
2 H₂(g) + O₂(g) → 2 H₂O(g)
Next, we use the molar mass of hydrogen to convert the mass of hydrogen to moles:
10.5 g H₂ × ⅛ mol H₂/2 g = 5.25 mol H₂
According to the stoichiometry of the reaction, 2 moles of hydrogen produce 2 moles of water. Therefore, 5.25 moles of hydrogen will produce:
5.25 mol H₂ × (2 mol H₂O/2 mol H₂) = 5.25 mol H₂O
The number of moles of water produced is 5.25.