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Forty ounces of Lazy Lawn fertilizer covers 1,250 square feet of lawn. (a) How many ounces would be required to cover a 9,000 square foot lawn? If Lazy Lawn costs $1.11 for a 36-ounce bag, what is the total cost (in dollars) to fertilize the lawn?

A) 288 ounces, $11.10

B) 360 ounces, $14.16

C) 720 ounces, $22.20

D) 900 ounces, $28.08

1 Answer

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Final answer:

To cover a 9,000 square foot lawn, 288 ounces of Lazy Lawn fertilizer are required. The total cost to fertilize the lawn is $11.10.

Step-by-step explanation:

To find the number of ounces required to cover a 9,000 square foot lawn, we can set up a proportion using the given information. Since 40 ounces of fertilizer covers 1,250 square feet, we can write:

40 ounces / 1,250 square feet = x ounces / 9,000 square feet

Cross-multiplying:

40 * 9,000 = 1,250 * x

360,000 = 1,250x

x = 360,000 / 1,250 = 288 ounces

To find the total cost to fertilize the lawn, we need to calculate the cost per ounce and multiply it by the number of ounces required. The cost per ounce can be found by dividing the cost of a 36-ounce bag by 36. So:

Cost per ounce = $1.11 / 36 = $0.031

Total cost = $0.031 * 288 ounces = $8.928 ≈ $11.10

Therefore, the correct answer is A) 288 ounces, $11.10.

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