Final answer:
The probability of offspring with genotype AaBbcc from a cross between AABbCc and AaBbCc is 1/8, calculated by multiplying the chance of each allele combination.
Step-by-step explanation:
To determine the probability of offspring with the genotype AaBbcc when crossing AABbCc with AaBbCc, we can use Mendel's principles of segregation and independent assortment.
- For the A allele, the first parent can only pass on A, while the second parent has a 1/2 chance of passing on a.
- For the B allele, the first parent has a 1/2 chance of passing on b, and the second parent also has a 1/2 chance of passing on b.
- For the C allele, the first parent can only pass on c, while the second parent has a 1/2 chance of passing on c.
Thus, the overall probability is the product of probabilities for each gene: (1/2 * 1/2 * 1/2), which equals 1/8.
The probability of offspring having the genotype AaBbcc from the cross AABbCc *x* AaBbCc is 1/8. Therefore, the correct answer is A) 1/8.