Question

If p(x) =6 (x2+2) +5, what is the value of p(11)?

Answer 1

The value of the polynomial p(x) = 6(x^2+2) + 5 when evaluated at x = 11 is found by substituting 11 into the equation, resulting in a value of 743 after calculation.

Step-by-step explanation:

The student is asking for the value of a polynomial function p(x) evaluated at x = 11. The polynomial is given as p(x) = 6(x2+2) + 5. To find p(11), we substitute x with 11 and follow the order of operations:

1. Compute the value inside the parentheses: 112 + 2.
2. Multiply the result by 6: 6 * (result from step 1).
3. Add 5 to the result from step 2.

Performing the calculations:

1. 112 + 2 = 121 + 2 = 123.
2. 6 * 123 = 738.
3. 738 + 5 = 743.

Therefore, the value of p(11) is 743.